If a concentration of 10 fluorescent molecules per μm2of cell membrane is needed to visualize a cell under the microscope, how many molecules of dye would be needed to visualize a single egg? Enter your answer in scientific notation rounded to two significant figures.

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PBCHEM

Answer : 78500 molecules of dye would be needed to visualize a single egg.

Explanation : An single egg cell has an diameter of 100 μm which is an approximate value.

To calculate the area of the cell membrane we can use this formula.

A = π [tex] (100)^{2} / 4 [/tex];

Therefore, A = 3.14 X [tex] (100)^{2} / 4 [/tex]

So, A =  7850 μ[tex]m^{2}[/tex]

Now. to calculate the amount of dye molecules needed for 10 fluorescent molecules / μ[tex]m^{2}[/tex]

will be;

as 1 μ[tex]m^{2}[/tex] = 7850 μ[tex]m^{2}[/tex] dye molecules.

Then 10 fluorescent molecules will need;

7850 X 10 = 78500 molecules of dye.

Therefore, the answer is 78500 molecules of dye.