We use the kinematic equation,to determine the time required for the motorcycle to reach the car's speed.
[tex]v=u+at[/tex]
Here, v is the velocity of motorcycle after time t, and u is the initial velocity and police motorcycle moves with acceleration a.
Given [tex]v=79 km/h=\frac{79\times10^3 m}{60\times60s} =21.9 m/s[/tex] and [tex]a=7.9 m/s^2[/tex] . Take [tex]u=0[/tex].
Substituting these values in above equation we get,
[tex]21.9 m/s=0+7.9 m/s^2\times t\\\\t =\frac{21.9m/s}{7.9 m/s^2} =2.77 s[/tex]
Thus, the motorcycle is moving as fast as the car after 2.77 s.
