contestada

An underwater diver sees the sun 57 ∘ above horizontal. how high is the sun above the horizon to a fisherman in a boat above the diver?

Respuesta :

Blacklash

Angle at which under water diver sees the sun from horizontal = [tex]57^{0}[/tex]

Angle from normal direction =  90 - 57 = [tex]33^{0}[/tex]

Refractive index of water = 1.33

Refractive index of water = 1

We have the equation

   1.33 * sin [tex]33^{0}[/tex]= 1 *sin [tex]\alpha[/tex]

 [tex]\alpha[/tex] = [tex]sin ^{-1} (\frac{1.33sin33}{1} )= 46.42^0[/tex]

This angle is angle from normal, so angle seen by fisherman from horizontal = 90 - 46.42 = [tex]43.58^{0}[/tex]

Ver imagen Blacklash
onyebuchinnaji

The angle above the horizontal to a fisherman in a boat above the diver is   43.6⁰.

Incident angle

The incident angle is the angle between the plane the normal. The incident angle is calculated as follows;

i = 90 - 57 = 33

Apply Snell's law to determine the angle of refraction

[tex]n_1 sin\theta_1 = n_2 sin\theta_2\\\\\theta _2 = sin^{-1}(\frac{n_1 sin\theta_1}{n_2} )\\\\\theta _2 = sin^{-1}(\frac{1.33 \times sin\33}{1} )\\\\\theta _2 = 46.4 ^o[/tex]

The angle above the horizontal to a fisherman in a boat above the diver = 90 - 46.4 = 43.6⁰.

Learn more about Snell's law here: https://brainly.com/question/13879937

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