Respuesta :
solution:
[tex]Fx= 22cos45°+ 14 cos30°\\ =27.68 lb\\ along y axis Fy= 22sin45°- 14 sin30°\\ =8.55634 j^ so magnitude is sqrt(Fx^2+Fy^2)\\ =28.97 lb\\ and angle is arc(Fy/Fx)\\ = 17.17 °[/tex]
Answer:
given theeta=45 in the first and 30 in the second quadrant,so solve the problem,we have measure angle from +x axis frame of reference
Fx=30 cos45+18 cos*330
Fx=21.21+15.6
Fx=36.8 lb
Fy=30 Sin45+18sin330
Fy=12.21 lb
Fr=sqrt(fx^2+fy^2)
Fr=38.77 lb
Resultant theeta=215