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Three point charges are located on the positive x-axis of a coordinate system. charge q1 = 1.5 nc is 2.0 cm from the origin, charge q2 = -3.5 nc is 4.0 cm from the origin and charge q3 = 4.5 nc located at the origin. what is the net force ((a)magnitude and (b) direction) on charge q1 = 1.5 nc exerted by the other two charges?]

Respuesta :

Force on charge q1 due to q2

[tex]F_1 = \frac{kq_1q_2}{r^2}[/tex]

[tex]F_1 = \frac{9*10^9 * 1.5 * 10^{-9}* 3.5 * 10^{-9}}{(0.04 - 0.02)^2}[/tex]

[tex]F_1 = 1.18 * 10^{-4} N[/tex] towards right

Force on charge q1 due to q3

[tex]F_2 = \frac{kq_1q_3}{r^2}[/tex]

[tex]F_2 = \frac{9*10^9 * 1.5 * 10^{-9}* 4.5 * 10^{-9}}{( 0.02)^2}[/tex]

[tex]F_2 = 1.52 * 10^{-4} N[/tex] towards right

Now the total force on charge q1 is given as

[tex]F = F_1 + F_2[/tex]

[tex]F = 1.52 * 10^{-4} + 1.18 * 10^{-4}[/tex]

[tex]F = 2.7 * 10^{-4} N[/tex]

Direction is towards + x or towards right

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