The net charge inside the cylinder is [tex]1.778*10^-^1^1C[/tex]
To solve this problem, we have to determine the electric flux
φc = EAcosθ
where θ is the angle between area vector and electric field.
θ = 90°, cos90° = 0
φc = EA * 0 = 0
The flux through the curved surface = 0
when x > 0
φ1 = EA cos0 = φ1 = EA *1 = EA
when x < 0
φ = E.A = EA*cos0
φ2 = EA
Net Flux of charge = φ(net) = φ(c) + φ1 + φ2 = 0 + EA + EA
φ(net) = 2EA
From Gauss Law
[tex]Q_n_e_t = \frac{net charge inside the cylinder}{E_0}\\ E_n_e_t = Net charge inside the cylinder = E_o * Q_n_e_t\\E_n_e_t = E_o*2EA[/tex]
given that;
ε = 8.85*10^-12 c^2/Nm^2
A = πr^2
r = 0.09m
Substitute the value into φ(net)
[tex]Q_n_e_t=8.85*10^-^1^2*200*2\pi (0.041)^2\\Q_n_e_t=1.778*10^-^1^1C[/tex]
From the calculations above, the net charge inside the cylinder is 1.778*10^-11C
learn more about electric flux here;
https://brainly.com/question/1592046