Let the tension in the thread will be at angle theta
now by force balance in x and y directions we can say
[tex]17 cos\theta = 18 cos60[/tex]
[tex]17 cos\theta = 9[/tex]
[tex]\theta = 58.03 degree[/tex]
now for the height of the kite we can use
[tex]h = L sin\theta[/tex]
[tex]h = 38 sin58.03[/tex]
[tex]h = 32.23 m[/tex]
so it will be at height 32.23 m from ground