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Points a, b, and c are at the corners of an equilateral triangle of side 1 m. equal positive charges of 5 c are at a and
b. (a) what is the potential at point c?

Respuesta :

Solution:

we know that the potential of any point is given by

v= kq/r^2............(1)

According to the question we have point charges is applied only two point so we must multiply the above equation by 2.

Then we get

V=2kq/r^2        [since charge is unity].

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