We have the equation for electric field E = kQ/[tex]d^{2}[/tex]
Where k is a constant, Q is the charge of source and d is the distance from center.
In this case E is inversely proportional to [tex]d^{2}[/tex]
So, [tex]\frac{E_{1} }{E_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}[/tex]
[tex]E_{1}[/tex] = 485 N/C
[tex]d_{1}[/tex] = 0.208 cm
[tex]d_{2}[/tex] = 0.620 cm
[tex]E_{2}[/tex] = ?
[tex]\frac{485 }{E_{2}} = \frac{0.620^{2}}{0.208^{2}}[/tex]
[tex]E_{2}[/tex] = [tex]\frac{485*0.208^{2}}{0.628^{2}}[/tex]
[tex]E_{2}[/tex] = 53.20 N/C
Solution:
we have given that the following:-
d=0.208cm
r=0,1cm
E=485N/C
we have to find at r=0.620cm
thus for the calculation of that we have to suppose the imaginary surface of sphere
Imaginary surfaces are spheres of radii 0.208cm and 0.620cm
485x4π 0.198²=E'x4π 0.586²
so,
E'.= 485x4π 0.198²/4π 0.586²
=19.01394/0.34396
= 55.37NC.
