Respuesta :
Solution:
According to the formula I=V/R
so 9.0v/2.5ohm=3.6A
since 3.6A=3.6c/s
therefore for per minute
3.6*60=216c leaving the battery.
Now,
Each electron carries a charge of 1.6*10^(-19)c
so 216/ 1.6*10^(-19)=1.35*10^21c
1.35*10^21c this is the required electrons leaving the battre per minute.
As the problem depicts the 9v battery is connected to the bulb of resistance 2.5ω, the electrons leaving the battery per minute are [tex]135\times10^{19}[/tex] electrons.
What is ohms law?
Ohms law states that the voltage across a conductor is directly proportional to the current flowing through it.
According to the ohms law,
[tex]V=I\times R[/tex]
where,
V= Voltage
I= Current
R= Resistance
Putting the given data we get,
[tex]V=I\times R[/tex]
[tex]9=I\times 2.5[/tex]
[tex]I=\frac{9}{2.5}[/tex]
[tex]I= 3.6 A[/tex][tex]=3.6c/s[/tex]
Now we have to find the electrons leaving per minute so,
[tex]I=3.6\times 60 C/min.[/tex]
[tex]I=216C/min[/tex]
As we know each electron has a charge of [tex]1.6\times 10^{-19} C[/tex]
So no. of electrons leaving per minute = [tex]\dfrac{216}{1.6\times10^{-19} }[/tex]
=[tex]135\times10^{19}[/tex] electrons/minute
To know more about Ohms law,
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