contestada

Enter the function below in the form p=p0at. Does it represent exponential growth or exponential decay? P=2e−0.5t round the base of the exponential function, a, to four decimal places

Respuesta :

we are given

[tex]P=2e^{-0.5t}[/tex]

we have to write this in

[tex]P=P_0a^{t}[/tex]  form

we can rewrite our function as

[tex]P=2(e^{-0.5})^t[/tex]

we can simplify value inside parenthesis

we get

[tex]P=2(0.6065)^t[/tex]

now, we can compare it with

[tex]P=P_0a^{t}[/tex]  form

and find 'a'

we get

[tex]a=0.6065[/tex]

Since,

[tex]a=0.6065<1 [/tex]

so, this is exponential decay function.........Answer

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