Respuesta :
Use one of the equations of motion under constant acceleration:-
s = ut + 0.5at^2 where s = distance, u - initial velocity, a = acceleration ( in this case it is gravity = 9.81 m s^-2) and t = time.
here we have s = 25*2 + 0.5*9.81 * 2^2
= 69.62 meters answer
Answer: The height of the building is 69.6 m
Explanation:
To calculate the height of the building, we use second equation of motion:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where,
s = height of the building = ?
u = initial velocity of the ball = 25 m/s
a = acceleration due to gravity = [tex]9.8m/s^2[/tex]
t = time taken = 2.0 sec
Putting values in above equation, we get:
[tex]s=(25\times 2.0)+\frac{1}{2}\times 9.8\times (2.0)^2\\\\s=69.6m[/tex]
Hence, the height of the building is 69.6 m
