Answer:
486.68 g
Solution:
Data Given:
Number of Molecules = 9.15 × 10²⁴
M.Mass of Methanol = 32.04 g.mol⁻¹
Mass of Methanol = ?
Step 1: Calculate Moles of Methanol,
Moles = Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹
Putting value,
Moles = 9.15 × 10²⁴ Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹
Moles = 15.19 mol
Step 2: Calculate Mass of Methanol:
Moles = Mass ÷ M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Putting values,
Mass = 15.19 mol × 32.04 g.mol⁻¹
Mass = 486.68 g
Solution:
first we have to calculate the mass of 1 mole of CH3OH?
C = 12
H3 = 3x1 = 3
O = 16
H =1
total mass 12+3+16+1=32g.
Total 32g So we know 6.02x10^23 molecules weigh in32g
therefore,
1 molecule weighs 32/6.02x10^23 g
now,
9.95x10^24 molecules weighs 9.95x10^24 x (32/6.02x10^23) = 9.95x32x10/6.02=99.5x32/6.02
=528.90g
thus the mass in grams is 528.90g.
