The mass in grams of 1.20 x10^21 molecules of asprin is 0.359 grams
calculation
find the number of moles of aspirin by use of Avogadro's law that is 1 mole =6.02 x10^23 molecules
what of 1 .20 x10^21 molecules
= (1 mole x 1.20 x10 ^21 molecules)/6.02 x10^23 molecules)= 1.993 x10^-3 moles
mass of aspirin= moles x molar mass
molar mass of aspirin = (12 x9)+(1 x8) +(16x4)=180 g/mol
mass= 1.993 x10^-3 moles x180 g/mol = 0.359 grams
Answer: The mass of given number of molecules of aspirin is 0.359 grams.
Explanation:
We are given:
Number of molecules of aspirin = [tex]1.20\times 10^{21}[/tex]
We know that:
Molar mass of aspirin [tex](C_9H_8O_4)[/tex] = 180.16 g/mol
According to mole concept:
[tex]6.022\times 10^{23}[/tex] number of molecules are contained in 1 mole of a compound
Also, [tex]6.022\times 10^{23}[/tex] number of molecules of aspirin has a mass of 180.16 grams
So, [tex]1.20\times 10^{21}[/tex] number of molecules will have a mass of [tex]\frac{180.16}{6.022\times 10^{23}}\times 1.20\times 10^{21}=0.359g[/tex]
Hence, the mass of given number of molecules of aspirin is 0.359 grams.
