Answer:
So, coordinate of intersection point = (2,0)
Explanation:
Given a triangle DCE whose coordinate of the vertex are :
D(−4, 0), C(0, −2), and E(5,3)
We will find the equation of CE
Firstly find the slope of CE
Slope (m) = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1}}[/tex]
m = [tex]\frac{3-(-2)}{5-0}[/tex] = 1
Equation of line is :
y - y₁ = m(x - x₁)
y - (-2) = 1(x-0)
y + 2 = x equation of CE
Find the intersection point of CE and x-axis
Put y = 0 to find the x-intercept
0 + 2 = x
x = 2
So, coordinate of intersection point = (2,0)
