From the definition of average velocity,
[tex]\bar v=\dfrac{\Delta y}{\Delta t}=\dfrac{49\,\mathrm m}t[/tex],
and the fact that constant acceleration means
[tex]\bar v=\dfrac{v_f+v_0}2=\dfrac{30\,\frac{\mathrm m}{\mathrm s}}2=15\,\dfrac{\mathrm m}{\mathrm s}[/tex]
we can solve for the time [tex]t[/tex]:
[tex]15\,\dfrac{\mathrm m}{\mathrm s}=\dfrac{49\,\mathrm m}t\implies t=3.3\,\mathrm s[/tex]