A translation 3 units to the left has a rule:
(x,y)→(x-3,y).
Then the image point of the point Q(2, −1) will be:
Q(2, −1)→Q'(2-3,-1)=Q'(-1,-1).
Answer: Q'(-1,-1)
Answer: The co-ordinates of the image of point Q(3, -1) are (-1, -1).
Step-by-step explanation: Given that the point Q(2, -1) is translated 3 units left.
We are to find the co-ordinates of the image of point Q.
The rule for the translation of 3 units left of a point (x, y) is given by
(x, y) ⇒ (x-3, y).
So, when Q(2, -1) is translated 3 units left, its co-ordinates becomes
Q(2, -1) ⇒ Q'(2-3, -1) = Q'(-1, -1).
Thus, the co-ordinates of the image of point Q(3, -1) are (-1, -1).
