Respuesta :

Answer: ∠JKM = [tex]106\textdegree[/tex] and

 ∠JKM = [tex]74\textdegree[/tex]

Step-by-step explanation:

Since we have given that

∠JKM=10y+6

∠MKL=8y-6

Since they are linear pairs ,

So, [tex]10y+6+8y-6=180\textdegree \\\\18y=180\textdegree \\\\y=\frac{180\textdegree}{18\textdegree}\\\\y=10\textdegree[/tex]

∠JKM = [tex]10\times 10+6=100+6=106\textdegree[/tex]

and

∠MKL = [tex]8\times 10-6=80-6=74\textdegree[/tex]

johanrusli

y = 10°

∠MKL = 74°

∠JKM = 106°

Further explanation

Firstly , let us learn about trigonometry in mathematics.

Suppose the ΔABC is a right triangle and ∠A is 90°.

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

There are several trigonometric identities that need to be recalled, i.e.

[tex]cosec ~ A = \frac{1}{sin ~ A}[/tex]

[tex]sec ~ A = \frac{1}{cos ~ A}[/tex]

[tex]cot ~ A = \frac{1}{tan ~ A}[/tex]

[tex]tan ~ A = \frac{sin ~ A}{cos ~ A}[/tex]

Let us now tackle the problem!

This problem is about Supplementary Angles.

∠MKL + ∠JKM = 180°

( 8y - 6 ) + ( 10y + 6 ) = 180°

18y = 180°

y = 180° / 18

y = 10°

∠MKL = ( 8y - 6 )° = (8 ( 10 ) - 6)° = 74°

∠JKM = ( 10y + 6 )° = (10 ( 10 ) + 6)° = 106°

Learn more

  • Calculate Angle in Triangle : https://brainly.com/question/12438587
  • Periodic Functions and Trigonometry : https://brainly.com/question/9718382
  • Trigonometry Formula : https://brainly.com/question/12668178

Answer details

Grade: College

Subject: Mathematics

Chapter: Trigonometry

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse  

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