The equation of the line in its generic form is given by:
[tex]y-yo = m (x-xo)[/tex]
Where,
m: slope of the line
(xo, yo): point that belongs to the line
Substituting values we have:
[tex]y - (- 3) = -6 (x - (- 2))[/tex]
Rewriting the equation we have:
[tex]y + 3 = -6 (x + 2)[/tex]
[tex]y + 3 = -6x-12[/tex]
[tex]y = -6x-12-3[/tex]
[tex]y = -6x-15[/tex]
Answer:
The equation of the line is given by:
[tex]y = -6x-15[/tex]
