Marty and Ethan both wrote a function, but in different ways.

Marty
y+3=1/3(x+9)

Ethan
x y
-4 9.2
-2 9.6
0 10
2 10.4

Whose function has the larger slope?

1. Marty’s with a slope of 2/3
2. Ethan’s with a slope of 2/5
3. Marty’s with a slope of 1/3
4. Ethan’s with a slope of 1/5

Respuesta :

Answer:

Option 3 is correct

Marty’s with a slope of 1/3

Step-by-step explanation:

Using slope intercept form:

The equation of line is: [tex]y=mx+b[/tex]          ....[1]

where,

m is the slope and b is the y-intercept.

Formula for Slope is given by:

[tex]\text{Slope} = \frac{y_2-y_1}{x_2-x_1}[/tex]         ....[2]

As per the statement:

Marty and Ethan both wrote a function, but in different ways.

Marty equation is:

[tex]y+3 = \frac{1}{3}(x+9)[/tex]

using distributive property [tex]a \cdot(b+c) = a\cdot b + a\cdot c[/tex] we have;

[tex]y+3 = \frac{1}{3}x+3[/tex]

Subtract 3 from both sides we have;

[tex]y= \frac{1}{3}x[/tex]

On comparing with [1] we have;

Slope of Marty = [tex]\frac{1}{3}=0.333..[/tex]

Ethan wrote a function:

Consider any two values from the table we have;

(0, 10) and (2, 10.4)

Substitute these in [2] we have;

[tex]\text{Slope} = \frac{10.4-10}{2-0}=\frac{0.4}{2} =0.2[/tex]

Slope of Ethan = 0.2

[tex]\text{Slope of Ethan} < \text{Slope of Marty}[/tex]

Therefore, . Marty’s with a slope of 1/3 function has the larger slope

Answer:

Marty’s with a slope of 1/3

Step-by-step explanation:

Marty

y+3=(1/3)*(x+9)

y + 3 = (1/3)*x + 3

y = (1/3)*x

Marty's slope: 1/3

To calculate Ethan’s slope we use the following formula :

m = (y2 - y1)/(x2 - x1)

where (x1, y1) and (x2, y2) are points of the function. Replacing with points (0,10) and (2, 10.4) we get:

m = (10.4 - 10)/(2 - 0) = 1/5

Ethan’s slope: 1/5