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chad had a garden in the shape of a rectangle. it’s length was twice it’s width. he decided to make a new garden that was 2 feet longer and 2 feet wider then his first garden. if x represents the original width of the garden, what is the difference, in square feet,between the area of his new garden and the area of the original garden

Respuesta :

calculista

Let

x--------> represents the original width of the garden

y-------> represents the original length of the garden

we know that

y=2x

the area of the original garden is equal to

A1=x*y-------> A1=x*(2x)------> A1=2x^{2}

the area of the new garden is

A2=(x+2)*(y+2)------>(x+2)*(2x+2) ------> A2=2x^{2}+2x+4x+4

A2=2x^{2}+6x+4

Find the difference between the area of his new garden and the area of the original garden

A2-A1=[2x^{2}+6x+4]-[2x^{2}]-------> 6x+4

therefore

the answer is

6x+4

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