[tex]f(x)+mx+b\to y=mx+b[/tex]
We have two points:
[tex](-4,\ -8);\ (0,\ -4)[/tex]
The point slope form of the line:
[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
substitute
[tex]m=\dfrac{-4-(-8)}{0-(-4)}=\dfrac{4}{4}=1\\\\y-(-8)=1(x-(-4))\\\\y+8=x+4\ \ \ |-8\\\\y=x-4[/tex]
Answer:
[tex]f(x)=x-4[/tex]
