If a large marshmallow has a volume of 2.00 in3 and density of 0.242 g/cm3, how much would it weigh in grams? 1 in3=16.39 cm3.

Respuesta :

First convert the inches cubed to centimeters cubed. Looking at the rate, we can write 2 inches cubed = 2 * 16.39 cm cubed = 32.78 cm cubed.

The equation for density is D = M/V, where D is the density, M is the mass, and V is the volume. Substitute the values into the equation:

0.242 = M/32.78

Multiply by 32.78 on both sides.

The mass is about 7.93 grams.

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically,         Density = [tex]\frac{mass}{volume}[/tex]

It is given that volume is 2 [tex]in^{3}[/tex] or 32.774 [tex]cm^{3}[/tex] (as 1 [tex]in^{3}[/tex] = 16.39 [tex]cm^{3}[/tex]). Density is given as 0.242 [tex]g/cm^{3}[/tex].

Hence, calculate the mass of marshmallow as follows.

                     Density = [tex]\frac{mass}{volume}[/tex]

             0.242 [tex]g/cm^{3}[/tex] = [tex]\frac{mass}{32.774 cm^{3}}[/tex]

                       mass = 7.93 g

Thus, we can conclude that mass of given marshmallow is 7.93 g.