Respuesta :
Remark
Sometimes you can avoid the distributive property. This is one of those cases. Start by dividing by 5. You can only do this is there a common factor between the left and right sides of the equal sign.
Solve
There is only 1 solution. If there was an x^2 somewhere, you would have 2 and if there was an x^3 there would be 3.
5(2x - 3) = 5 Divide both sides by 5
5(2x - 3)/5 = 5/5
(2x - 3) = 1 Remove the brackets.
2x - 3 = 1 Add 3 to both sides.
2x = 1 + 3
2x = 4 Divide by 2
x = 4/2
x = 2 <<<<< Answer
Part A:
It has One Solution
Part B:
Step 1: 5(2x - 3) = 5
Step 2: (5 x 2x) - (5 x 3) = 5
Step 3: 10x - 15 = 5
Step 4: 10x - (15 + 15) = 5 + 15
Step 5: 10x - 0 = 20
Step 6: 10x = 20
Step 7: (10x ÷ 10) = (20 ÷ 10)
Step 8: x = 20/10
Step 9: x = 20/10 = 2
Step 10: x = 2