Point P is in the interior of ∠OZQ. If m∠OZQ = 125° and m∠OZP = 62°, what is m∠PZQ?

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lublana lublana · Answer 1 · 2019-08-23T12:09:07+02:00

Answer:

[tex]\angle PZQ=63^{\circ}[/tex]

Step-by-step explanation:

We are given that point P is interior of angle OZQ.

We are given that angle OZQ =[tex]125^{\circ}[/tex]

The measure of angle OZP=[tex]62^{\circ}[/tex]

Angle OZQ=Angle OZP+Angle PZQ

Substitute the values

Then, we get

[tex]62+\angle PZQ=125[/tex]

[tex]\Angle PZQ=125-62[/tex]

Using by subtraction property of equality

[tex]\angle PZQ=63^{\circ}[/tex]

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abidemiokin abidemiokin · Answer 2 · 2021-09-17T16:04:16+02:00

The measure of m∠PZQ is 63degrees

The point where two lines meet or intersect is known as an angle.

If point P is in the interior of ∠OZQ, then:

<OZQ = <OZP + m∠PZQ

Given the following angles:

m∠OZQ = 125°

m∠OZP = 62°

Substitute the given values into the expression above:

125 = 62 + m∠PZQ

m∠PZQ = 125 - 62

m∠PZQ = 63degrees

Hence the measure of m∠PZQ is 63degrees

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