a block of iron has a mass of 826g. what is the mass of a block of magnesium that has the same volume as the block of iron? the density of magnesium is 1.7 g/cm3, and the density of the iron is 7.9 g/cm3.

Respuesta :

Answer is: the mass of a block of magnesium is 177.75 grams.

m(Fe) = 826 g.

d(Fe) = 7.9 g/cm³.

1) Calculate volume of iron and magnesium:

d(Fe) = m(Fe) ÷ V(Fe).

V(Fe) = m(Fe) ÷ d(Fe).

V(Fe) = 826 g ÷ 7.9 g/cm³.

V(Fe) = V(Mg) = 104.56 cm³.

2) Calculate mass of magnesium:

m(Mg) = V(Mg) · d(Mg).

m(Mg) = 104.56 g/cm³ · 1.7 g/cm³.

m(Mg) = 177.75 g.

The mass of the block of magnesium that has the same volume as the block of iron is 177.752 g

What is density?

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

How to determine the volume of the iron

  • Mass of iron = 826 g
  • Density of iron = 7.9 g/cm³
  • Volume of iron =?

Volume = mass / density

Volume of iron = 826 / 7.9

Volume of iron = 104.56 cm³

How to determine the mass of magnesium

  • Volume of iron = 104.56 cm³
  • Density of magnesium = 1.7 g/cm³
  • Volume of magnesium = Volume of iron = 104.56 cm³
  • Mass of magnesium =?

Mass = Density × Volume

Mass of magnesium = 1.7  × 104.56

Mass of magnesium = 177.752 g

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