Respuesta :
Answer is: the mass of a block of magnesium is 177.75 grams.
m(Fe) = 826 g.
d(Fe) = 7.9 g/cm³.
1) Calculate volume of iron and magnesium:
d(Fe) = m(Fe) ÷ V(Fe).
V(Fe) = m(Fe) ÷ d(Fe).
V(Fe) = 826 g ÷ 7.9 g/cm³.
V(Fe) = V(Mg) = 104.56 cm³.
2) Calculate mass of magnesium:
m(Mg) = V(Mg) · d(Mg).
m(Mg) = 104.56 g/cm³ · 1.7 g/cm³.
m(Mg) = 177.75 g.
The mass of the block of magnesium that has the same volume as the block of iron is 177.752 g
What is density?
The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
How to determine the volume of the iron
- Mass of iron = 826 g
- Density of iron = 7.9 g/cm³
- Volume of iron =?
Volume = mass / density
Volume of iron = 826 / 7.9
Volume of iron = 104.56 cm³
How to determine the mass of magnesium
- Volume of iron = 104.56 cm³
- Density of magnesium = 1.7 g/cm³
- Volume of magnesium = Volume of iron = 104.56 cm³
- Mass of magnesium =?
Mass = Density × Volume
Mass of magnesium = 1.7 × 104.56
Mass of magnesium = 177.752 g
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