PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Solve for y.
4y2 = 196

4y² = 196
[tex]\frac{4y^{2} }{4}[/tex] = [tex]\frac{196}{4}[/tex]
y² = 49
√y² = √49
|y| = 7
=/- y = 7
y = 7 , y = -7
Answer: 7, -7
[tex]4y^2=196\ \ \ |:4\\\\y^2=49\to y=\pm\sqrt{49}\\\\y=\pm7\\\\Answer:\ y=-7\ or\ y=7[/tex]