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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Factor the expression completely over the complex numbers.

y3 + 2y2 + 16y + 32

PLEASE HELP ASAP CORRECT ANSWER ONLY PLEASE Factor the expression completely over the complex numbers y3 2y2 16y 32 class=

Respuesta :

gmany

[tex]y^3+2y^2+16y+32=y^2(y+2)+16(y+2)=(y+2)(y^2+16)\\\\=(y+2)(y^2-(4i)^2)=(y+2)(y-4i)(y+4i)\\\\Used:\ a^2-b^2=(a-b)(a+b)[/tex]

     y³ + 2y²      +       16y + 32

= y²(y + 2)        +     16(y + 2)

= (y² + 16) (y + 2)

Note: y² + 16  = y² - (-16)   is the difference formula: √(y²)  - √(-16)²  = (y + 4i)(y - 4i)

Answer: (y - 4i)(y + 4i)(y + 2)