The dimensions of field are [tex]0.1020 km\times 0.0640 km[/tex]. The area can be calculated as follows:
[tex]A=l\times b=0.1020 km\times 0.0640 km=6.526\times 10^{-3}km^{2}[/tex]
Converting [tex]km^{2}\rightarrow m^{2}[/tex],
1 km =1000 m
Thus, [tex]1km^{2}=10^{6}m^{2}[/tex]
or, [tex]6.526\times 10^{-3}km^{2}=6.526\times 10^{3}m^{2}[/tex]
Since, cost of new artificial turf is [tex]\$ 9.50/m^{2}[/tex], thus, cost for [tex]6.526\times 10^{3}m^{2}[/tex] will be:
[tex]Cost= \$ 9.50/m^{2}\times 6.528\times 10^{3}m^{2}=\$ 62016[/tex]
Therefore, cost of artificial turf for field will be [tex]\$ 62016[/tex].
