You're partly right.
[tex]x^2=484\\\\\sqrt{x^2}=\sqrt{484}\qquad\text{square root both sides}\\\\|x|=\sqrt{484}\qquad\text{root of $x^2$}\\\\x=\pm\sqrt{484}=\pm 22[/tex]
In the expression ±√(484), we say the root is "indicated". That is, we are showing we want the root. The expression ±22 is the actual root—the result of carrying out the root-taking process.
