a)
the average speed, well it does 10 ft in 1.6 secs, so is simply their quotient, 10/1.6 = 6.25 ft/s on average.
b)
over the horizontal, well, it covered horizontally 9.25 ft in those 1.6 secs, so their quotient is 9.25/1.6 = 5.78125 ft/s on average.
c)
we don't know the vertical distance, but
[tex]\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad
\begin{cases}
c=\stackrel{10}{hypotenuse}\\
a=\stackrel{9.25}{adjacent}\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{10^2-9.25^2}=b\implies \sqrt{14.4375}=b\implies 3.8\approx b[/tex]
so, it covered vertically about 3.8 ft in those 1.6 secs, so then 3.8/1.6 = 2.375 ft/s on average
