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You want to find the area of the front of a house, whose shape is a triangle on top of a rectangle with a width of 12. The triangle's height is 14 and the rectangle's height is 5. What is the total area of the front of the house?

Respuesta :

sid071

There are two shapes

rectangle and triangle

Rectangle area = Length × breadth

Triangle area = ( 1 / 2 ) × height × base

L = 12

W = 5

Area = 60

Height = 14

base = width of rectangle

base = 12

( 1 / 2 ) ( 12 ) ( 14 )

( 14 ) ( 6 )

84

Total area = 60 + 84

= 144

Hope helps!

The total area of the front of the house is 144.

The area of my house is the sum of the area of my rectangle and the area of the triangle.

A rectangle is a quadrilateral. Opposite sides are equal.

Area of a rectangle = length x width

12 x 5 = 60

A triangle is a polygon with three sides.

Area of a triangle = [tex]\frac{1}{2}[/tex] × base × height

[tex]\frac{1}{2}[/tex] × 12 × 14 = 84

Sum of the areas = 84 + 60 = 144.

Please find attached images of a triangle and a rectangle. To learn more, please check: https://brainly.com/question/11687957

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