If points a,b,c,d and ,e are collinear and in that order. Find AC if AE = x+50 and CE=x+32

Hence, we get: AC= 18
It is given that:
A,B,C,D and E are collinear and in that order.
Also, we are asked to find the length of the line segment AC.
given that the length of the line segment AE is:
AE=x+50
and the length of the line segment CE is given by:
CE=x+32
Now we know that:
the length of the line segment AC is length of line segment AE minus the length of the line segment CE.
i.e.
[tex]AC=AE-CE\\\\AC=x+50-(x+32)[/tex]
on opening the parentheses term we have:
[tex]AC=x+50-x-32\\\\AC=x-x+50-32\\\\AC=0+18\\\\AC=18[/tex]
The Line Segment AC has a length of 18 units.
From Geometry and definition of Line Segment, we know that measure of the Line Segment AE is:
[tex]AE = AC + CE[/tex] (1)
If we know that [tex]AE = x + 50[/tex] and [tex]CE = x + 32[/tex], then the measured of the Line Segment AC is:
[tex]AC = AE - CE[/tex]
[tex]AC = (x +50) - (x+32)[/tex]
[tex]AC = 18[/tex]
The Line Segment AC has a length of 18 units.
Please see this question related to Line Segments: https://brainly.com/question/18379737