We need to solve for x. Let's try problem b:
[tex]2x-6=3x+1-x-7[/tex]
Let us first combine line terms. 3x and -x as well as 1 and -7 can be combined. Let's do that:
[tex]2x-6=2x-6[/tex]
Since this is true, your answer would be:
All real numbers
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Let's solve for problem c:
[tex]3x+1=43[/tex]
Let's isolate x, so subtract 1 from both sides:
[tex]3x=42[/tex]
Since x can't have a coefficient, divide both sides by 3:
[tex]\frac{3x}{3}=\frac{42}{3}[/tex]
[tex]x=14[/tex]
So, only the value of 14 would make this equation true.
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Let's try problem d:
[tex]4x-1=4x+7[/tex]
Let's get our whole numbers on the right side. Add 1 to both sides:
[tex]4x=4x+8[/tex]
Subtract 4x from the right side on both sides:
[tex]0=8[/tex]
Since this is not true, your answer would be:
No solution
