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In how many grams of water should 25.31 g of potassium nitrate (kno3) be dissolved to prepare a 0.1982 m solution?

Respuesta :

Solution:

Molality:-It is a measure of the concentration of a solute in a solution in terms of amount of substance in a specified amount of mass of the solvent

Therefore,  

Molality = moles solute / kg solvent  

Therefore kg solvent = moles solute / molality  

moles solute = mass / molar mass  

= 25.31 g / 101.1 g/mole  

= 0.2503 mole

kg solvent = 0.2503 mole / 0.1982 m  

= 1.263 kg  

= 1263 g

This is the required answer.

Answer: The mass of water that is needed to dissolve the given amount of potassium nitrate is 1263.1g

Explanation:

To calculate the mass of solvent for given molality of solution, we use the equation:

[tex]\text{Molality of solution}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}[/tex]

where,

Molality of the solution = 0.1982 m

[tex]m_{solute}[/tex] = Given mass of solute [tex](KNO_3)[/tex] = 25.31 g

[tex]M_{solute}[/tex] = Molar mass of solute [tex](KNO_3)[/tex] = 101.1 g/mol

[tex]W_{solvent}[/tex]= Mass of solvent (water) = ?

Putting values in above equation, we get:

[tex]0.1982=\frac{25.31\times 1000}{101.1\times \text{Mass of water}}\\\\\text{Mass of water}=\frac{25.31\times 1000}{101.1\times 0.1982}=1263.1g[/tex]

Hence, the mass of water that is needed to dissolve the given amount of potassium nitrate is 1263.1g