we are given
[tex]f(x,y,z) = (x + y')' z + (xz)' + y[/tex]
we can expand and simplify it
step-1: Distribute complement
[tex]f(x,y,z) = (x)'(y')'z + x'+z' + y[/tex]
step-2: Simplification
[tex]f(x,y,z) = x'yz + x'+z' + y[/tex]
[tex]f(x,y,z) = x'(yz + 1)+z' + y[/tex]
[tex]f(x,y,z) = x'+z'+y[/tex]..................Answer