Answer:-
0.91% is the students % of error
Explanation: -
Accepted value= 12.11 grams
Measured value = 12.22 grams
Error = 12.22-12.11 = 0.11 grams
Percentage error = [tex]\frac{0.11 grams}{12.11 grams}[/tex]x100
= 0.91 %
Thus 0.91% is the students % of error