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One swimmer in a relay race has a 0.53 s lead and is swimming at a constant speed of 4.49 m/s. The swimmer has 55.3 m to swim before reaching the end of the pool. A second swimmer moves in the same direction as the leader. What constant speed must the second swimmer have in order to catch up to the leader at the end of the pool? Answer in units of m/s.

Respuesta :

this is a relay race and is not answer able
aachen

Answer:

[tex]4.69\ m/s[/tex]

Explanation:

Speed of first swimmer, v = 4.49 m/s.

Distance travelled by first swimmer, d = 55.3 m.

Therefore, time taken by him to reach the end , t = [tex]\dfrac{55.3}{4.49}=12.31 \ s[/tex].

Since, second swimmer has to reach the end position in the same time with first swimmer. But since first swimmer is at a lead of 0.53 s.

Therefore, time he have to do the task, [tex]T=12.31-0.53=11.78\ s[/tex].

And he have to travel the same distance d=55.3 m.

Therefore, velocity, [tex]u=\dfrac{d}{T}=\dfrac{55.3}{11.78}=4.69 \ m/s[/tex].

Hence, it is the required solution.

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