parallel lines have the same exact slope.... hmmm so what the slope of that equation there? low and behold, the equation is already in slope-intercept form, meaning
[tex]\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{slope-intercept form}\\
\cline{1-1}
\\
y=\stackrel{\stackrel{slope}{\downarrow }}{m}x+b\\
\\\\
\cline{1-1}
\end{array}~\hspace{10em}y=\stackrel{slope}{\cfrac{1}{5}}x-6[/tex]
so a parallel line to that one, will also have a slope of 1/5, so we're really looking for the equation of a line whose slope is 1/5 and runs through 1,6.
[tex]\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{6})~\hspace{10em}
slope = m\implies \cfrac{1}{5}
\\\\\\
\begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-6=\cfrac{1}{5}(x-1)\implies y-6=\cfrac{1}{5}x-\cfrac{1}{5}
\\\\\\
y=\cfrac{1}{5}x-\cfrac{1}{5}+6\implies y=\cfrac{1}{5}x+\cfrac{29}{5}[/tex]
