Let the required number is 2x ,
According to the condition,
➡ 10 times the sum of half of 2x and 6 = 8
[tex] = > 10 \times ( \frac{2x}{2} + 6) = 8 \\ \\ \\ = > 10 \times (x + 6) = 8 \\ \\ \\ = > 10x + 60 = 8 \\ \\ \\ = > 10x = 8 - 60 \\ \\ \\ = > 10x = - 52 \\ \\ \\ = > x = - \frac{ 52}{10} \\ \\ \\ = > x = - 5.2[/tex]
Therefore the value of x is -5.2
And, required number is -5.2
