As we know that it has all given data given as
[tex]v_i = 14 m/s[/tex]
[tex]v_f = 25 m/s[/tex]
distance moved = 0.250 km = 250 m
now we can use kinematics to find acceleration
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
[tex]25^2 - 14^2 = 2 * a * 250[/tex]
[tex]a = 0.86 m/s^2[/tex]
so it will accelerate at rate of 0.86 m/s^2
