Respuesta :

Remark

There is no short way to do this problem and no obvious way to get the answer other that to solve each part.  

Solve

A

[tex]\dfrac{x + 1.6}{2} =\text{x + 0.1}[/tex]                    Multiply by 2

x + 1.6 = 2(x + 0.1)                                         Remove the brackets

x + 1.6 = 2x + 0.1*2                                        

x + 1.6 = 2x + 0.2                                          Subtract x from both sides

1.6 = x + 0.2                                                  Subtract 0.2 from both sides  

1.6 - 0.2 = x                        

1.4 = x

Circle A

B

Subtract 2x from both sides.

3x - 2x = 1.4

Circle B

C

Remove the brackets.

4x + 6 = 2x - 6           Add 6 to both sides

4x + 12 = 2x               Subtract 4x from both sides.

12 = -2x                      Divide by - 2

12/-2 = x

x = - 6                         Don't circle C

D

I'm going to be very scant in my solution of this. You can fill in the steps.

3x = 4.2

x = 4.2/3

x = 1.4

Circle D

A.) [tex]\frac{(x + 1.6)}{2} = x + 0.1 = x + 1.6 = 2x + 0.2 = x - 2x = -1.6 + 0.2[/tex]

x = 1.4

B.)  [tex]3x = 2x + 1.4[/tex]

Subtract 2x from both sides, which makes 3x - 2x = 1.4

3x - 2x = x, so x = 1.4.

C.) 4x + 6 = 2(x - 3)

First distribute on the right side:

2(x - 3) = 2x - 6

4x + 6 = 2x - 6

2x - 4x = 6 + 6

-2x = 12

x = -6

D.) 7x - 3.2 = 4x + 1

This can be rewritten as 7x - 4x = 3.2 + 1

3x = 4.2

x = 1.4

C is the only incorrect answer.