Can someone give me the answers plz:)

Remark
There is no short way to do this problem and no obvious way to get the answer other that to solve each part.
Solve
A
[tex]\dfrac{x + 1.6}{2} =\text{x + 0.1}[/tex] Multiply by 2
x + 1.6 = 2(x + 0.1) Remove the brackets
x + 1.6 = 2x + 0.1*2
x + 1.6 = 2x + 0.2 Subtract x from both sides
1.6 = x + 0.2 Subtract 0.2 from both sides
1.6 - 0.2 = x
1.4 = x
Circle A
B
Subtract 2x from both sides.
3x - 2x = 1.4
Circle B
C
Remove the brackets.
4x + 6 = 2x - 6 Add 6 to both sides
4x + 12 = 2x Subtract 4x from both sides.
12 = -2x Divide by - 2
12/-2 = x
x = - 6 Don't circle C
D
I'm going to be very scant in my solution of this. You can fill in the steps.
3x = 4.2
x = 4.2/3
x = 1.4
Circle D
A.) [tex]\frac{(x + 1.6)}{2} = x + 0.1 = x + 1.6 = 2x + 0.2 = x - 2x = -1.6 + 0.2[/tex]
x = 1.4
B.) [tex]3x = 2x + 1.4[/tex]
Subtract 2x from both sides, which makes 3x - 2x = 1.4
3x - 2x = x, so x = 1.4.
C.) 4x + 6 = 2(x - 3)
First distribute on the right side:
2(x - 3) = 2x - 6
4x + 6 = 2x - 6
2x - 4x = 6 + 6
-2x = 12
x = -6
D.) 7x - 3.2 = 4x + 1
This can be rewritten as 7x - 4x = 3.2 + 1
3x = 4.2
x = 1.4
C is the only incorrect answer.