we know that
A half-acre is equal to----------> [tex]2,023.43\ m^{2}[/tex]
Let
x---------> the length side of the building lot
y--------> the width side of the building lot
A------> Area of the building lot
x=5y-------> equation 1
[tex]A=2,023.43\ m^{2}[/tex]
[tex]A=x*y[/tex]
[tex]2,023.43=x*y[/tex] --------> equation 2
substitute equation 1 in equation 2
[tex]2,023.43=[5y]*y[/tex]
[tex]5y^{2}= 2,023.43\\y^{2}= 404.686\\y= 20.11\ m[/tex]
Find the value of x
[tex]x=5y---> x=5*20.11--> x=100.55 m[/tex]
therefore
the answer is
the dimensions of the building lot are 100.55 m* 20.11 m
