The isotope that occurs in greater abundance is Cl-35
We can obtain the answer to the question by simply calculating the abundance of each isotope.
Let isotope Cl-35 be A
Let isotope Cl-37 be B
From the question given above, the following data were obtained:
For A (isotope Cl-35)
Mass of A = 35
Abundance of A (A%) =?
For B (isotope Cl-37)
Mass of B = 37
Abundance of B (B%) = 100 – A
Atomic mass of chlorine = 35.453 amu
Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
35.453 = [(35 × A%)/100] + [(37 × (100 – A%))/100]
35.453 = 0.35A% + 37 – 0.37A%
Collect like terms
35.453 – 37 = 0.35A% – 0.37A%
–1.547 = –0.02A%
Divide both side by –0.02
A% = –1.547 / –0.02
A% = 77.35%
Abundance of B (B%) = 100 – A
Abundance of B (B%) = 100 – 77.35
Abundance of B (B%) = 22.65%
SUMMARY:
Isotope Cl-35 has abundance of 77.35%
Isotope Cl-37 has abundance of 22.65%
Therefore, isotope Cl-35 occurs in greater abundance.
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