1) Given [tex]f(x) = x^{3}[/tex]
[tex]f(bx) = (bx)^{3}= b^{3} x^{3}[/tex]
Since (0.5,8) lies on f(bx) , [tex]8=b^{3} 0.5^{3}[/tex]
Divide with [tex]0.5^{3}[/tex] on both sides
[tex]b^{3} = \frac{8}{0.5^{3} }[/tex]
= 64
[tex]b=64^{\frac{1}{3} } = 4[/tex]
Hence b=4.
2) Given (1,3) lies on y=f(x) plugin x=1 and y=3
that is f(1) = 3
We can find corresponding point for that in y=-2f(x) by plugging in x=1.
That is y= -2f(1) = -2*3 = -6
Hence point is (1,-6)
