Answer: See the figure attached.
Step-by-step explanation:
Observe the figure attached. The vertices of the triangle ABC have the following coordinates:
A(2,5); B(6,2) and C(3,-5)
To graph the image (in this case we can identify it as A'B'C'), you must use the rule [tex](x,y)[/tex]→[tex](x-6,y-4)[/tex].
Then, you have to subtract 6 units from the x-coordinate of each vertex and subtract 4 units from the y-coordinate of each vertex.
Therefore, you get:
Vertex A'→ [tex](2-6,5-4)=(-4,1)[/tex]
Vertex B'→ [tex](6-6,2-4)=(0,-2)[/tex]
Vertex C'→ [tex](3-6,-5-4)=(-3,-9)[/tex]
Having the vertices of the image A'B'C', you can graph it (See the figure attached).
