[tex]\bf \cfrac{7}{2}x-8.62-\cfrac{3}{2}x-2.38\implies \cfrac{7}{2}x-\cfrac{3}{2}x-8.62-2.38\implies \cfrac{7x-3x}{2}-11 \\\\\\ \cfrac{4x}{2}-11\implies 2x-11[/tex]
[tex]\frac{7}{2}x-8.62-\frac{3}{2}x-2.38\\ \\ (\frac{7}{2}x-\frac{3}{2}x)+(-8.62-2.38)\\ \\ (\frac{4}{2}x)+(-11)\\ \\ 2x-11[/tex]
This should be your final answer.
