we are given that
angle(ACF)=90
angle(ACB)=61
sum of all angles along any line is 180
so, we get
angle(ACF)+angle(ACD)=180
we can plug value
90+angle(ACD)=180
angle(ACD)=90
now, we can use formula
angle(ACD)=angle(ACB)+angle(BCD)
now, we can plug values
and we get
90=61+angle(BCD)
90-61=61-61+angle(BCD)
angle(BCD)=29................Answer
Answer:
Step-by-step explanation:
In the given diagram,
m(∠ACB) + m(∠ACf) +m(∠FCE) = 180°
[Angles formed at point on a straight line]
It is given that m(∠ACB) = 61°
m(∠ACF) = 90°
Therefore, 61° + 90° + m(∠FCE) = 180°
151 + m(∠FCE) = 180
m(∠FCE) = 180 - 151
= 29°
Since m(∠FCE) = (∠BCD)
[vertical opposite angles]
Therefore, m(∠BCD) = 29°
