Given : Initial velocity = -1.3 m/s
Final Velocity = -6.5 m/s.
Time = 25 minutes.
To find : Average acceleration.
Solution: We are given units in meter/second (m/s).
So, we need to convert time 25 minutes in seconds.
1 minute = 60 seconds.
25 minutes = 60*25 = 1500 seconds.
Formula for average acceleration is given by,
[tex]\frac{Final \ velocity -Initial \ velocity}{Final \ time - Initial \ time }[/tex]
We are not given intial time, so we can take initial time =0.
Plugging values in the above formula.
[tex]Average \ acceleration = \frac{-6.5 -(-1.3)}{1500-0}[/tex]
= [tex]\frac{-5.2}{1500}[/tex]
= -0.003467
or [tex]Average \ acceleration = -3.467 \times 10^{-3}\ m/s^2.[/tex].
Answer:
The average acceleration of the treadmill during this period is 0.00346 m/s²
Explanation:
It is given that,
Initial velocity of the treadmill, u = 1.3 m/s
After 25 minutes, the treadmill has a velocity of 6.5 m/s
Final velocity of the treadmill, v = 6.5 m/s
Time taken, t = 25 minutes = 1500 seconds
We need to find the average acceleration of the treadmill during this period. It is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{6.5\ m/s-1.3\ m/s}{1500\ s}[/tex]
[tex]a=0.00346\ m/s^2[/tex]
So, the average acceleration of the treadmill during this period is 0.00346 m/s². Hence, this is the required solution.
