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The solubility of oxygen gas in water at 40 ∘c is 1.0 mmol/l of solution. What is this concentration in units of mole fraction? The solubility of oxygen gas in water at 40 is 1.0 of solution. What is this concentration in units of mole fraction? 1.80×10−5 1.80×10−2 1.00×10−2 5.55×10−2 1.00×10−6

Respuesta :

The formula for mole fraction is:

[tex]mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}[/tex]    -(1)

The solubility of oxygen gas = 1.0 mmol/L  (given)

1.0 mmol/L means 1.0 mmol are present in 1 L.

Converting mmol to mol:

[tex]1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol[/tex]

So, moles of oxygen = 0.001 mol

For moles of water:

1 L of water = 1000 mL of water

Since, the density of water is 1.0 g/mL.

[tex]Density = \frac{mass}{volume}[/tex]

[tex]Mass = 1.0 g/ml\times 1000 mL = 1000 g[/tex]

So, the mass of water is 1000 g.

Molar mass of water = 18 g/mol.

Number of moles of water = [tex]\frac{1000 g}{18 g/mol} = 55.55 mol[/tex]

Substituting the values in formula (1):

[tex]mole fraction = \frac{0.001}{55.55+0.001}[/tex]

[tex]mole fraction = 1.8\times 10^{-5}[/tex]

Hence, the mole fraction is [tex]1.8\times 10^{-5}[/tex].

ajeigbeibraheem

The solubility of oxygen gas in water at 40° C is 1.0 mmol/l of solution. The concentration in units of mole fraction is 1.80 × 10⁻⁵.

In 1 Liter of a solution, the solubility of 1.0 mmol/L is expressed as:

[tex]\mathbf{= 1.0 \ mmol \times \dfrac{1 \ mol}{1000 \ mmol} }[/tex]

= 0.001 mol of oxygen.

However, the moles of water in 1L is calculated as follows;

  • We know that 1 L of water = 1000 mL of water.
  • suppose we make an assumption that the density of the water is 1.0 g/mL

Then using the formula for density which is:

  • density = mass/volume

Making mass the subject of the formula:

  • Mass = density × volume
  • Mass = 1.0 g/mL× 1000 mL
  • Mass of water = 1000 g

Now, the number of moles of the water can be estimated using the formula:

number of moles = mass(g)/molar mass

The number of moles of water = 1000 g/ 18.02 g/mol

The number of moles of water = 55.49 moles

Finally, for the mole fraction of oxygen, we have:

[tex]{\text}mole fraction of oxygen = \dfrac{\text{moles of oxygen }}{\text{total moles in the system}}[/tex]

[tex]{\text}mole fraction of oxygen = \dfrac{\text{0.001 moles }}{\text{55.49 moles }}[/tex]

mole fraction of oxygen = 1.80 × 10⁻⁵.

Learn more about mole fractions here:

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